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Molar massLead(II) nitrate
Molar mass of Pb(NO3)2 (Lead(II) nitrate)
The molar mass of Pb(NO3)2 is 331.21 g/mol.
Mixed with potassium iodide it makes the yellow precipitate in golden rain.
Step-by-step calculation
Add up the atomic masses of every atom in the formula:
1 × 207.2 + 2 × 14.007 + 6 × 15.999 = 331.21 g/mol
| Element | Atoms | Atomic mass (u) | Subtotal (g/mol) | % by mass |
|---|---|---|---|---|
| Lead (Pb) | 1 | 207.2 | 207.200 | 62.56% |
| Nitrogen (N) | 2 | 14.007 | 28.014 | 8.46% |
| Oxygen (O) | 6 | 15.999 | 95.994 | 28.98% |
| Molar mass of Pb(NO3)2 | 331.21 g/mol | |||
Moles to grams for Pb(NO3)2
Multiply the number of moles by 331.21 g/mol to get the mass, and divide a mass by 331.21 g/mol to get the moles.
| Amount (mol) | Mass (g) | Mass (g) | Amount (mol) |
|---|---|---|---|
| 0.1 mol | 33.12 g | 1 g | 0.0030 mol |
| 0.25 mol | 82.80 g | 5 g | 0.0151 mol |
| 0.5 mol | 165.60 g | 10 g | 0.0302 mol |
| 1 mol | 331.21 g | 50 g | 0.1510 mol |
| 2 mol | 662.42 g | 100 g | 0.3019 mol |
| 5 mol | 1656.04 g | 500 g | 1.5096 mol |
Frequently asked questions
What is the molar mass of Pb(NO3)2?
The molar mass of Pb(NO₃)₂ (lead(ii) nitrate) is 331.21 g/mol, so one mole of lead(ii) nitrate weighs 331.21 grams.
How do you calculate the molar mass of Pb(NO3)2?
Multiply each element’s atomic mass by the number of atoms in the formula and add the results: 1 × 207.2 + 2 × 14.007 + 6 × 15.999 = 331.21 g/mol.
What percentage of Pb(NO3)2 is lead?
Lead makes up 62.56% of the mass of Pb(NO₃)₂.
How many grams are in one mole of Pb(NO3)2?
One mole of Pb(NO₃)₂ has a mass of 331.21 grams, and contains 6.022 × 10²³ formula units.