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Molar massIron(III) oxide
Molar mass of Fe2O3 (Iron(III) oxide)
The molar mass of Fe2O3 is 159.69 g/mol.
Rust; it reacts with aluminium in the thermite reaction.
Step-by-step calculation
Add up the atomic masses of every atom in the formula:
2 × 55.845 + 3 × 15.999 = 159.69 g/mol
| Element | Atoms | Atomic mass (u) | Subtotal (g/mol) | % by mass |
|---|---|---|---|---|
| Iron (Fe) | 2 | 55.845 | 111.690 | 69.94% |
| Oxygen (O) | 3 | 15.999 | 47.997 | 30.06% |
| Molar mass of Fe2O3 | 159.69 g/mol | |||
Moles to grams for Fe2O3
Multiply the number of moles by 159.69 g/mol to get the mass, and divide a mass by 159.69 g/mol to get the moles.
| Amount (mol) | Mass (g) | Mass (g) | Amount (mol) |
|---|---|---|---|
| 0.1 mol | 15.97 g | 1 g | 0.0063 mol |
| 0.25 mol | 39.92 g | 5 g | 0.0313 mol |
| 0.5 mol | 79.84 g | 10 g | 0.0626 mol |
| 1 mol | 159.69 g | 50 g | 0.3131 mol |
| 2 mol | 319.37 g | 100 g | 0.6262 mol |
| 5 mol | 798.44 g | 500 g | 3.1311 mol |
Experiments that use iron(iii) oxide
⚖️ Calculate any other formulaFrequently asked questions
What is the molar mass of Fe2O3?
The molar mass of Fe₂O₃ (iron(iii) oxide) is 159.69 g/mol, so one mole of iron(iii) oxide weighs 159.69 grams.
How do you calculate the molar mass of Fe2O3?
Multiply each element’s atomic mass by the number of atoms in the formula and add the results: 2 × 55.845 + 3 × 15.999 = 159.69 g/mol.
What percentage of Fe2O3 is iron?
Iron makes up 69.94% of the mass of Fe₂O₃.
How many grams are in one mole of Fe2O3?
One mole of Fe₂O₃ has a mass of 159.69 grams, and contains 6.022 × 10²³ formula units.