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Molar massSilver nitrate
Molar mass of AgNO3 (Silver nitrate)
The molar mass of AgNO3 is 169.87 g/mol.
Used to test for halide ions and to grow a silver tree on copper.
Step-by-step calculation
Add up the atomic masses of every atom in the formula:
1 × 107.87 + 1 × 14.007 + 3 × 15.999 = 169.87 g/mol
| Element | Atoms | Atomic mass (u) | Subtotal (g/mol) | % by mass |
|---|---|---|---|---|
| Silver (Ag) | 1 | 107.87 | 107.870 | 63.50% |
| Nitrogen (N) | 1 | 14.007 | 14.007 | 8.25% |
| Oxygen (O) | 3 | 15.999 | 47.997 | 28.25% |
| Molar mass of AgNO3 | 169.87 g/mol | |||
Moles to grams for AgNO3
Multiply the number of moles by 169.87 g/mol to get the mass, and divide a mass by 169.87 g/mol to get the moles.
| Amount (mol) | Mass (g) | Mass (g) | Amount (mol) |
|---|---|---|---|
| 0.1 mol | 16.99 g | 1 g | 0.0059 mol |
| 0.25 mol | 42.47 g | 5 g | 0.0294 mol |
| 0.5 mol | 84.94 g | 10 g | 0.0589 mol |
| 1 mol | 169.87 g | 50 g | 0.2943 mol |
| 2 mol | 339.75 g | 100 g | 0.5887 mol |
| 5 mol | 849.37 g | 500 g | 2.9434 mol |
Experiments that use silver nitrate
⚖️ Calculate any other formulaFrequently asked questions
What is the molar mass of AgNO3?
The molar mass of AgNO₃ (silver nitrate) is 169.87 g/mol, so one mole of silver nitrate weighs 169.87 grams.
How do you calculate the molar mass of AgNO3?
Multiply each element’s atomic mass by the number of atoms in the formula and add the results: 1 × 107.87 + 1 × 14.007 + 3 × 15.999 = 169.87 g/mol.
What percentage of AgNO3 is silver?
Silver makes up 63.50% of the mass of AgNO₃.
How many grams are in one mole of AgNO3?
One mole of AgNO₃ has a mass of 169.87 grams, and contains 6.022 × 10²³ formula units.