Molar mass of CuSO4·5H2O (Copper(II) sulfate pentahydrate)
The molar mass of CuSO4·5H2O is 249.68 g/mol.
The blue crystals of copper sulfate; it contains five waters of crystallisation.
Step-by-step calculation
Add up the atomic masses of every atom in the formula:
1 × 63.546 + 1 × 32.065 + 9 × 15.999 + 10 × 1.008 = 249.68 g/mol
| Element | Atoms | Atomic mass (u) | Subtotal (g/mol) | % by mass |
|---|---|---|---|---|
| Copper (Cu) | 1 | 63.546 | 63.546 | 25.45% |
| Sulfur (S) | 1 | 32.065 | 32.065 | 12.84% |
| Oxygen (O) | 9 | 15.999 | 143.991 | 57.67% |
| Hydrogen (H) | 10 | 1.008 | 10.080 | 4.04% |
| Molar mass of CuSO4·5H2O | 249.68 g/mol | |||
Moles to grams for CuSO4·5H2O
Multiply the number of moles by 249.68 g/mol to get the mass, and divide a mass by 249.68 g/mol to get the moles.
| Amount (mol) | Mass (g) | Mass (g) | Amount (mol) |
|---|---|---|---|
| 0.1 mol | 24.97 g | 1 g | 0.0040 mol |
| 0.25 mol | 62.42 g | 5 g | 0.0200 mol |
| 0.5 mol | 124.84 g | 10 g | 0.0401 mol |
| 1 mol | 249.68 g | 50 g | 0.2003 mol |
| 2 mol | 499.36 g | 100 g | 0.4005 mol |
| 5 mol | 1248.41 g | 500 g | 2.0025 mol |
Frequently asked questions
What is the molar mass of CuSO4·5H2O?
The molar mass of CuSO₄·5H₂O (copper(ii) sulfate pentahydrate) is 249.68 g/mol, so one mole of copper(ii) sulfate pentahydrate weighs 249.68 grams.
How do you calculate the molar mass of CuSO4·5H2O?
Multiply each element’s atomic mass by the number of atoms in the formula and add the results: 1 × 63.546 + 1 × 32.065 + 9 × 15.999 + 10 × 1.008 = 249.68 g/mol.
What percentage of CuSO4·5H2O is oxygen?
Oxygen makes up 57.67% of the mass of CuSO₄·5H₂O.
How many grams are in one mole of CuSO4·5H2O?
One mole of CuSO₄·5H₂O has a mass of 249.68 grams, and contains 6.022 × 10²³ formula units.