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Molar massAcetic acid
Molar mass of CH3COOH (Acetic acid)
The molar mass of CH3COOH is 60.05 g/mol.
The weak acid that gives vinegar its sour taste.
Step-by-step calculation
Add up the atomic masses of every atom in the formula:
2 × 12.011 + 4 × 1.008 + 2 × 15.999 = 60.05 g/mol
| Element | Atoms | Atomic mass (u) | Subtotal (g/mol) | % by mass |
|---|---|---|---|---|
| Carbon (C) | 2 | 12.011 | 24.022 | 40.00% |
| Hydrogen (H) | 4 | 1.008 | 4.032 | 6.71% |
| Oxygen (O) | 2 | 15.999 | 31.998 | 53.28% |
| Molar mass of CH3COOH | 60.05 g/mol | |||
Moles to grams for CH3COOH
Multiply the number of moles by 60.05 g/mol to get the mass, and divide a mass by 60.05 g/mol to get the moles.
| Amount (mol) | Mass (g) | Mass (g) | Amount (mol) |
|---|---|---|---|
| 0.1 mol | 6.01 g | 1 g | 0.0167 mol |
| 0.25 mol | 15.01 g | 5 g | 0.0833 mol |
| 0.5 mol | 30.03 g | 10 g | 0.1665 mol |
| 1 mol | 60.05 g | 50 g | 0.8326 mol |
| 2 mol | 120.10 g | 100 g | 1.6652 mol |
| 5 mol | 300.26 g | 500 g | 8.3261 mol |
Experiments that use acetic acid
⚖️ Calculate any other formulaFrequently asked questions
What is the molar mass of CH3COOH?
The molar mass of CH₃COOH (acetic acid) is 60.05 g/mol, so one mole of acetic acid weighs 60.05 grams.
How do you calculate the molar mass of CH3COOH?
Multiply each element’s atomic mass by the number of atoms in the formula and add the results: 2 × 12.011 + 4 × 1.008 + 2 × 15.999 = 60.05 g/mol.
What percentage of CH3COOH is oxygen?
Oxygen makes up 53.28% of the mass of CH₃COOH.
How many grams are in one mole of CH3COOH?
One mole of CH₃COOH has a mass of 60.05 grams, and contains 6.022 × 10²³ formula units.